Solving Op Amp Confusion with PWM Circuit

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Discussion Overview

The discussion revolves around a pulse width modulator (PWM) circuit utilizing operational amplifiers (op amps), specifically addressing the issue of a square wave not aligning with the x-axis in the waveform output. Participants explore the design and functionality of the circuit components, including a Schmitt trigger, integrator, comparator, and isolation stage.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant notes that the op amp design limits the output from reaching the negative or positive supply levels, which may explain the floating square wave.
  • Another participant suggests adding a FET buffer stage to ensure the signal reaches ground if that is a requirement.

Areas of Agreement / Disagreement

Participants present differing views on the cause of the floating square wave, with some attributing it to the op amp design limitations while others propose a potential solution without consensus on the best approach.

Contextual Notes

The discussion does not resolve the underlying assumptions regarding the op amp characteristics or the specific requirements for the PWM signal.

jafferrox
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Hi

In the waveform picture i attached, I don't know why the square wave is floating instead of being on the 0 of the x axis. I also attached schematic of the pwm circuit.

By the way, this is a pulse width modulator circuit made of 4 op amps, U2D is a schmitt trigger to generate sqaure wave, U2C is integrator that integrates square and generate triangle wave, U2A is comparator which is used to generate PWM signal and U2B is used to isolate pwm signal from the load that's going to connect to the output.

Thanks in advance
 

Attachments

  • pwm circuit.jpg
    pwm circuit.jpg
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  • sq wave.png
    sq wave.png
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The design of the opamp prevents the output from going all the way to the negative supply or all the way to the positive supply. There are other opamps, often called "rail-to-rail, with which the outputs do go to the positive and negative supplies.
 
You could add a simple 1 or 2 FET buffer stage to cause that signal to hit ground, if that were important.
 
thanks for the help guys.
 

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