Solving Oscillating Mass-Spring System w/ Non-Resonant Force

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Homework Help Overview

The discussion revolves around a mass-spring system subjected to a sinusoidal forcing function, where the frequency of the force differs from the system's natural frequency. Participants are exploring the implications of this setup on the system's behavior and the mathematical approach to solving the differential equation governing the motion.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formulation of the differential equation and the need to find both homogeneous and particular solutions. There is uncertainty about how to proceed without initial conditions and the implications of the frequency condition B ≠ √(k/m).

Discussion Status

Some participants have provided guidance on solving the differential equation, including steps for finding the general solution. However, there remains a lack of clarity regarding the role of initial conditions and how to interpret the results in terms of position and velocity.

Contextual Notes

There is a noted absence of initial conditions, which complicates the solution process. The distinction between the forcing frequency and the natural frequency is also a central point of discussion.

Yann
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1. Homework Statement and 2. Homework Equations

Find position/velocity of a mass m attached to a spring of constant k when subjected to an oscillatinf roce

<br /> F(t) = F sin(Bt)<br />

With B\not = \sqrt{k/m}

The Attempt at a Solution



Model;

<br /> mx&#039;&#039; + kx = F \sin(Bt)<br />

I have no idea if/how it can be solved (without a computer, of course). Because;

<br /> mr^2 + k = 0<br />

Gives

<br /> r = ±\sqrt{-k/m}<br />

As B\not = \sqrt{k/m} it can't be an answer.
 
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I'm not sure I understand your point, it's more a problem of math than a problem of physics, I must solve;

<br /> mx&#039;&#039; + kx = F \sin(Bt)<br />

But I don't know how
 
Yann said:
I'm not sure I understand your point, it's more a problem of math than a problem of physics, I must solve;

<br /> mx&#039;&#039; + kx = F \sin(Bt)<br />

But I don't know how

First solve the homogenous equation first:

mx'' + kx = 0

Then you need a particular solution for
<br /> mx&#039;&#039; + kx = F \sin(Bt)<br />

just plug in x = Asin(Bt) into the differential equation and solve for A...

Then your general solution is the solution for the homogenous equation + the particular solution Asin(Bt)...

And finally you need to deal with initial conditions...
 
Thx for the help, I solved the diff. equation. But will the solution to the differential equation give me the position or the velocity at time t ? And there's no initial condition, only B\not = \sqrt{k/m}, I don't know what to do with it.
 
You actually need two boundary conditions, but since you don't have them you can probably just leave the two constants unsolved for.
 

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