Solving Quadratic Equation: Find Roots of m+ni & m-ni

AI Thread Summary
If one root of the quadratic equation ax^2 + bx + c = 0 is m + ni, the other root is m - ni due to the properties of complex conjugates. This relationship can be derived from the quadratic formula, which states that roots come in conjugate pairs when coefficients are real. To demonstrate this, one can expand the expression (x - (m + ni))(x - (m - ni)) and confirm that it simplifies correctly to a quadratic equation. The discussion emphasizes the necessity of including the x^2 term in the expansion, as omitting it leads to an incorrect formulation. Understanding this concept is crucial for solving quadratic equations with complex roots.
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Homework Statement



If one of the roots of the quadratic equation, ax^2+bx+c=0 is m+ni, show that the other root is m-ni.

Homework Equations





The Attempt at a Solution



How do i actually show this? I mean it's a well known fact and a direct outcome of the quadratic formula. Is this valid?

(x-(m+ni))(x-(m-ni))=0

then x-2m+m^2+n^2=0
 
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thereddevils said:

Homework Statement



If one of the roots of the quadratic equation, ax^2+bx+c=0 is m+ni, show that the other root is m-ni.

Homework Equations





The Attempt at a Solution



How do i actually show this? I mean it's a well known fact and a direct outcome of the quadratic formula. Is this valid?

(x-(m+ni))(x-(m-ni))=0

then x-2m+m^2+n^2=0
The last equation above is not correct. For one thing, there should be an x2 term.

You are given that m + ni is a root of the equation ax2 + bx + c = 0, so it should be true that a(m + ni)2 + b(m + ni) + c = 0.

Expand the stuff on the left and you will get a complex number that must be zero.

Now, what do you need to do to show that m - ni is also a solution of the same quadratic equation?
 
Mark44 said:
The last equation above is not correct. For one thing, there should be an x2 term.

You are given that m + ni is a root of the equation ax2 + bx + c = 0, so it should be true that a(m + ni)2 + b(m + ni) + c = 0.

Expand the stuff on the left and you will get a complex number that must be zero.

Now, what do you need to do to show that m - ni is also a solution of the same quadratic equation?

thanks Mark!
 
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