Solving Radian Equation: Amp=2/3, Period=4╥, Shift=╥/2

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To create a sine function with an amplitude of 2/3, a period of 4π, and a phase shift of π/2, the correct equation is derived from the standard sine function format. The period affects the coefficient of the variable inside the sine function, which is calculated as 2π divided by the period, resulting in a coefficient of 1/2. The phase shift is incorporated by adjusting the angle inside the sine function accordingly. Therefore, the final equation should be y = (2/3) sin(1/2Θ - π/2). Understanding the definitions of period and phase shift is crucial for correctly formulating the sine function.
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Homework Statement


Write an equation of a sine function with a amp=(2/3) , Period = 4╥ and a phase shift of ╥/2.

in radians



Homework Equations





The Attempt at a Solution


i got

y = 2/3 cos (2...
 
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lucifer_x said:

Homework Statement


Write an equation of a sine function with a amp=(2/3) , Period = 4╥ and a phase shift of ╥/2.

in radians



Homework Equations





The Attempt at a Solution


i got

y = 2/3 cos (2...


Keep going... (and use the sin function)
 
so would the answer be

y = - 2/3 sin ( 2Θ + π )

and

y = 2/3 sin ( 2Θ + π )

??
 
lucifer_x said:
so would the answer be

y = - 2/3 sin ( 2Θ + π )

and

y = 2/3 sin ( 2Θ + π )

??

I don't think so. How is the period of these functions defined? How is the phase shift defined?
 
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