Solving Resonance: Ideas to Get Started

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To solve the resonance problem for a 143-cm-long pipe that is closed at one end, the key concept is understanding the relationship between frequency, wavelength, and the speed of sound. The relevant equation is frequency equals speed divided by wavelength (f = v/λ). For a closed pipe, resonance occurs at specific wavelengths that correspond to odd harmonics, typically where the length of the pipe equals one-quarter of the wavelength. The discussion emphasizes the need to identify whether to use 1/4, 1/2, or full wavelengths in calculations. Clarifying these concepts will help in determining the resonant frequencies of the pipe.
LTU83
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I don't want the answer to this problem just an idea of how to get started. I don't understand what I am looking for. Thanks.

Homework Statement



A 143-cm-long pipe is stopped at one end. Near the open end, there is a loudspeaker that is driven by an audio oscillator whose frequency can be varied from 10.0 to 4700 Hz. (Take the speed of sound to be 343 m/s.)


Homework Equations


freq= v / λ (just guessing)


The Attempt at a Solution

 
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I don't understand what you are looking for either. There is no question attached to the statement of the situation, but f = v/λ is correct regardless.
 
I presume you want to find the resonant frequency of the pipe. Let's narrow it down a bit. Will it be when the length of the pipe is equal to 1/4 wavelength, 1/2 wavelength or 1 wavelength of the frequency?
 

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