Solving Separable Equations: y'=xcos^(2)y

[btnh]

I am just supposed to find the general solution, in an explicit form if possible.

y'=xcos^(2)y

Thanks!

 

[sennyk]

Do your own HW.

I am just supposed to find the general solution, in an explicit form if possible.

y'=xcos^(2)y

Thanks!

This problem can be answered by someone with a strong grasp of calculus I. Get your calculus I book out.

Ken

 

[Matthew Rodman]

Multiply both sides by \sec^2{y}, to get

y^{\prime} \sec^2{y} = x

Now, integrate both sides w.r.t. x to get

\tan{y} = \frac{x^2}{2} + \kappa

where \kappa is a constant.