Solving simultaneous equations F = ma

AI Thread Summary
The discussion revolves around solving simultaneous equations related to Luke's weight and the acceleration of an elevator. Luke's scale readings change from 0.97 kN to 1.18 kN when he picks up a 20 kg box, prompting the need to find the elevator's acceleration and Luke's weight. Participants suggest focusing on each scale reading separately and substituting values to avoid confusion with units. The importance of maintaining consistent units and using symbolic representations until the end is emphasized for clarity. Ultimately, the key takeaway is to simplify the approach to solving the equations without combining them prematurely.
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Homework Statement



Luke stands on a scale in an elevator which has a constant acceleration upward. The scale reads 0.97 kN. When Luke picks up a box of mass 20 kg, the scale reads 1.18 kN. (The acceleration remains the same.) (a) Find the acceleration of the elevator. (b) Find Luke's weight.

Homework Equations


So I came up with 2 equations one for Luke w/o the added mass one for Luke with.
W_1 = m(g+a) I solve it for m.
m = W_1 / (a+g)
equation 2
W-2-(m+20)g=(m+20)a

The Attempt at a Solution


My strategy is to just solve both equation for m. Set them equal and then just plug and chug and get my my a. The issue is I can't solve the equation!
If my strategy is correct. The units don't work out at all. Apples and Oranges.
So,

W_2 - 20g - 20a / a+g =W_1/ a+g
Multiply both sides by a+g gave
W_2 - 20g -20a = W_1
Cleaning it up for a I got...

W_2 -20g - W_1 / 20 = a
See what I meant about apples and oranges something is wrong. I have been at it for a while I have tunnel vision.
Thanks to whoever helps
 
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Jbreezy said:

Homework Statement



Luke stands on a scale in an elevator which has a constant acceleration upward. The scale reads 0.97 kN. When Luke picks up a box of mass 20 kg, the scale reads 1.18 kN. (The acceleration remains the same.) (a) Find the acceleration of the elevator. (b) Find Luke's weight.


Homework Equations


So I came up with 2 equations one for Luke w/o the added mass one for Luke with.
W_1 = m(g+a) I solve it for m.
m = W_1 / (m+g)
What kind of solution for m is that??
 
I changed it I just meant m = W_1/ (a+g)
That is it. Sorry typo. Good catch.
 
I suggest you look at the problem without trying to solve for both weights simultaneously.

You know the scale readings before and after Luke picks up the 20 kg box.
Assuming the accel. in the elevator is the same for both scale readings, and assuming a typical g, then you should be able to find the acceleration of the elevator.
 
Hello StemKind,
I was actually not just solving for the weights. I know what the weights were. But you are saying I should be able to get this without combining my equations?
Thanks,
 
Jbreezy said:
I changed it I just meant m = W_1/ (a+g)
That is it. Sorry typo. Good catch.

Substitute into your W_2 equation to find a. Then get m.
 
yeah that is what I tried above the units are not correct. That is the strategy but something is wrong with my solution above.
 
Jbreezy said:
W_2 -20g - W_1 / 20 = a
Two things will help here. Include parentheses and either include units throughout or, better, keep everything symbolic until the end. E.g. if mb is the mass of the box (20kg):
(W2 -mbg - W1) / mb = a
... and everything's apples.
 
Ahh Thank you Haruspex.
Apples are quite good. Especially with peanut butter. I see the issue now.
 
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