Solving Spin 1/2 Interactions with Hilbert Space Dimensions and J$^2$

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SUMMARY

The discussion centers on the Hamiltonian for three distinguishable spin 1/2 particles, expressed as H = λ (S₁ · S₂ + S₂ · S₃ + S₃ · S₁). The dimension of the Hilbert space is confirmed to be 8D, derived from the formula (2 * 3/2 + 1). The Hamiltonian can be expressed in terms of J², where J = S₁ + S₂ + S₃, leading to the equation H = λ (1/2 J² - S₁² - S₂² - S₃²). The discussion also addresses the challenge of representing the Hamiltonian without residual spin operators.

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  • Understanding of quantum mechanics and spin systems
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  • Knowledge of angular momentum operators and their algebra
  • Experience with Hamiltonians in quantum mechanics
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Quantum physicists, students of quantum mechanics, and researchers working on spin systems and Hamiltonian dynamics will benefit from this discussion.

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Homework Statement



three distiguishable spin 1/2 particles interact via

H = \lamda ( S_1 \cdot S_2 + S_2 \cdot S_3 + S_3 \cdot S_1 )

a) What is the demension of the hilbert space?

b) Express H in terms of J^2 where J = S_1 + S_2 + S_3

c) I then need to find the energy and eigenstates, but i think i can due this once i know the hamilitonian.

Homework Equations


The Attempt at a Solution



a) would this be 6D, 2 from each particle? or
(2*3/2 + 1) = 4

or am i all wrong?

b) J^2 = S_1^2 + S_2^2 + S_3^2 + 2S_1S_2 + 2S_3S_2 + 2S_1S_3

H = \lamda (1/2 J^2 - _1^2 - S_2^2 - S_3^2)

but i still have S's in my H. Is this ok? I feel like its not.

should i use.. J^2 + \hbar J_z + J_+J_-?

why can't i just write everything as a 2x2 matrix, for the energies, then solve it that way without using J^2?
 
Last edited:
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so i know now that a) is 8D

and i think that H = J^2 - S^2 - S^2 - S^2
 

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