Solving Spring Problems Involving Mass and Frictionless Floor

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SUMMARY

The discussion focuses on a physics problem involving a block of mass 4.5 kg on a frictionless floor attached to a spring with a spring constant of 16 N/m and a relaxed length of 3 m. Key calculations include the spring extension, potential energy stored in the spring, maximum speed attained by the block, and the distance traveled before stopping. The user seeks assistance with calculating the acceleration of the block when the spring is fully stretched, having incorrectly applied the formula F = ma and the spring force equation F = -kx.

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  • Understanding of Hooke's Law and spring constants
  • Basic principles of potential energy in springs
  • Knowledge of kinematics and dynamics, particularly acceleration and force
  • Familiarity with the concept of frictionless surfaces in physics
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Physics students, educators, and anyone interested in solving mechanics problems involving springs and motion on frictionless surfaces.

Naeem
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A block of mass m = 4.5 kg rests on a frictionless floor. It is attached to a spring with a relaxed length L = 3 m. The spring has spring constant k = 16 N/m and is relaxed when hanging in the vertical position. The block is pulled d = 3 m to one side. In this problem, the block is always constrained to move on the floor (i.e. it never leaves the floor).


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a) By what amount is the spring extended?
DL = m *


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b) What is the potential energy stored in the spring?
Uspring = J *
12.3 OK


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c) The block is released but is constrained to move horizontally on the frictionless floor. What is the maximum speed it attains?
|v|max= m/s *
2.34 OK


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Let's change the problem a bit. When the spring is vertical (hence, unstretched), the block is given an initial speed equal to 1.8 times the speed found in part (c).
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d) How far from the initial point does the block go along the floor before stopping?
Dmax = m *
4.287 OK


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e) What is the magnitude of the acceleration of the block at this point (when the spring is stretched farthest)?
|a| = m/s2
0.638 NO

HELP: What is the force exerted by the spring on the block when the spring is fully stretched?

I am not able to figure out part e. I'm stuck

here is what I did F = ma = k * delta L

Plugged in m , k and delta L

found a to be 8.25 m/s2, which is wrong, anybody tell me what is wrong?
 
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The force a spring exerts on an object is F = -kx.
 
If the spring is vertical in its relaxed mode, and the block is move laterally, then the spring forms the hypotenuse of an isosceles right triangle with two sides of 3 m.

Here I am assuming the floor is horizontal with the normal parallel to the axis of the spring.
 
Can anybody help me with part e) here please.

Thanks,
 

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