Solving Static Friction Coefficient for Wooden Block on Table

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SUMMARY

The discussion focuses on calculating the coefficient of static friction for a wooden block with a mass of 29.0 kg on a horizontal table, when a 15.5 kg mass is attached to a wire over a frictionless pulley. The key equation used is Ff = coefficient * Fn, where Fn is the normal force. The normal force is calculated by considering the total weight acting on the block, which includes both the block and the hanging mass. The correct approach emphasizes isolating the forces acting on the block to accurately determine the static friction coefficient.

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Homework Statement



A wooden block of mass 29.0 kg sits on a horizontal table. A wire of negligible mass is attached to the right side of the block and goes over a pulley (also of negligible mass, and frictionless), where it is allowed to dangle vertically. When a mass of 15.5 kg is attached to the wire, the block barely starts to slide. What is the coefficient of static friction between block and table?

Homework Equations



f=ma
Ff=coefficient (Fn)

The Attempt at a Solution



Fn=(29+15.5)*9.8?

got stuck after that.
 
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hi runningirl! :smile:

no, the weight of the block acts on the block only, the weight of the 15.5 kg mass acts on the 15.5 kg mass only …

to find Fnormal for the block, consider only the forces on the block (including the tension) :wink:
 

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