Solving the Chain Rule Equation with Differential Calculus

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Homework Help Overview

The discussion revolves around the application of the chain rule in differential calculus, specifically in the context of partial derivatives and their relationships in a multivariable function.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the chain rule but questions the validity of their manipulation involving partial derivatives. Other participants express confusion and seek hints to clarify their understanding of the chain rule's application.

Discussion Status

Participants are actively engaging with the problem, with some offering alternative formulations of the chain rule and others expressing uncertainty about their previous attempts. There is a recognition of the need for clarification on the use of certain mathematical operations.

Contextual Notes

Some participants indicate a lack of confidence in their understanding of the concepts involved, particularly regarding the use of cross products in this context. There is an acknowledgment of the complexity of the problem and the need for further guidance.

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Homework Statement



2hedil3.png


Homework Equations





The Attempt at a Solution


a) (∂z/∂x)=-(∂f/∂x)*(∂z/∂f)

i used that (AxB)=-(BxA)
so i get

(∂z/∂x)=-[-(∂z/∂f)(∂f/∂x)]
=(∂z/∂x)
is this correct if not can someone give me hints pls

thanks
 
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i just realized that i can not use that cross product...now I am really lost help...someone pls give me a hint...pls
 
anyone? pls
 
Let f(x, y)= F(x, y, z(x,y))= 0 so that f is a constant function and all its partial derivatives are 0. Then
[tex]\frac{\partial f}{\partial x}= \frac{\partial F}{\partial x}+ \frac{\partial F}{\partial z}\frac{\partial z}{\partial x}= 0[/tex].

Solve that for
[tex]\frac{\partial z}{\partial x}[/tex].
 

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