Solving the Expansion of the Crab Nebula

  • Thread starter Thread starter Fizzicist
  • Start date Start date
  • Tags Tags
    Expansion Nebula
AI Thread Summary
The Crab Nebula, a remnant of a supernova observed in 1054 A.D., is expanding and emits red light due to heated hydrogen gas. The frequency of light received from the nebula is slightly higher than that produced in a laboratory, indicating its expansion velocity has been calculated. The challenge lies in estimating the nebula's diameter as of 2004 A.D., given the time since the explosion. The diameter can be determined using the known expansion speed and the time elapsed since the supernova. Understanding the time frame of the expansion is crucial for calculating the current diameter.
Fizzicist
Messages
53
Reaction score
0

Homework Statement



The gas cloud known as the Crab Nebula can be seen with even a small telescope. It is the remnant of a supernova, a cataclysmic explosion of a star. The explosion was seen on the Earth on July 4, 1054 a.d. The streamers glow with the characteristic red color of heated hydrogen gas. In a laboratory on the earth, heated hydrogen produces red light with frequency 4.568 * 10^14 Hz ; the red light received from streamers in the Crab Nebula pointed toward the Earth has frequency 4.586*10^14 Hz.

Find velocity of expansion (solved)

Assuming that the expansion speed has been constant since the supernova explosion, estimate the diameter of the Crab Nebula in 2004 a.d. Give your answer in light years.


Homework Equations




The equation for the doppler effect for light is fR = sqrt((c-v)/(c+v))fs with fR= frequency of waves heard by receiver, and fs = frequency of waves emitted by source.


The Attempt at a Solution



I don't know what the frequency of the waves emitted by the supernova is, only the frequency received. It looks like this equation has two unknowns (v and fs), so I don't know how to solve for v. Is there something I'm missing here?

Edit: I solved for the velocity. Apparently I had some numbers mixed up. Now I am having problems solving for the diameter. How do you find the diameter when you don't know how long it's been expanding?
 
Last edited:
Physics news on Phys.org
Fizzicist said:
How do you find the diameter when you don't know how long it's been expanding?

The diameter you are asked to find is the diameter as seen from the Earth now. The time it exploded as seen from Earth is given.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top