Solving the Mystery of an Unfamiliar Trig Identity

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SUMMARY

The discussion centers on the trigonometric identity presented by a professor: \(\frac{1}{2}\cos(2\theta) = \sin\theta \cos\theta\). Participants confirm that this identity is incorrect and suggest that the correct identity is \(\frac{1}{2}\sin(2\theta) = \sin\theta \cos\theta\). The integral \(\int \cos(2\theta) d\theta\) is also mentioned, with the correct expression being \(\sin\theta \cos\theta + C\). This highlights the importance of verifying trigonometric identities in calculus.

PREREQUISITES
  • Understanding of trigonometric identities
  • Knowledge of integral calculus
  • Familiarity with the double angle formulas
  • Ability to manipulate trigonometric expressions
NEXT STEPS
  • Study the derivation of the double angle formulas for sine and cosine
  • Practice solving integrals involving trigonometric functions
  • Explore common trigonometric identities and their proofs
  • Learn about the applications of trigonometric identities in calculus
USEFUL FOR

Students of calculus, mathematics educators, and anyone seeking to deepen their understanding of trigonometric identities and their applications in integration.

thenewbosco
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Today the professor wrote down the following for use in an integral:

[tex]\frac{1}{2}cos(2\theta)=sin\theta cos\theta[/tex]

i am not sure is this is correct. i have tried to prove this and cannot, i have also not found it in an table of trig identities. Is this a valid identity? i am not sure since this prof always makes mistakes
 
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It should be [tex]\frac{1}{2}\sin 2\theta = \sin\theta \cos\theta[/tex]
 
He probably meant

[tex]\int \cos 2\theta = \sin\theta \cos\theta +c[/tex]

Daniel.
 

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