Solving the Mystery of P(P(∅))

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Madonna M.
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1. Homework Statement

How many elements does this set have?

* P(P(∅))

2. Homework Equations

I know that if a set has n elements, then its power set has 2^n elements but i really want to know if (P(∅)) is just one element or not.

Thanks in advance..
 
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How many subsets does ##\emptyset## have?
 
Madonna M. said:
1. Homework Statement

How many elements does this set have?

* P(P(∅))

2. Homework Equations

I know that if a set has n elements, then its power set has 2^n elements but i really want to know if (P(∅)) is just one element or not.

Thanks in advance..

Sure it is. The empty set has one subset. Itself. But remember P is the SET of subsets. So P(∅) isn't ∅. It's {∅}. There is a difference.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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