- #1

- 584

- 0

- Thread starter Benny
- Start date

- #1

- 584

- 0

- #2

- 3,763

- 9

Is x function of y ? is y function of x ? Or both x and y function of some other argument ?

Your are gonna need to be a bit more specific here

marlon

- #3

- 349

- 0

- #4

- 584

- 0

- #5

saltydog

Science Advisor

Homework Helper

- 1,582

- 3

Hey Benny, you got this? It's a particular form of the Riccati Equation right?Benny said:

[tex]y^{'}+Q(x)y+R(x)y^2=P(x)[/tex]

so yours is:

[tex]y^{'}-y^2=x^2[/tex]

Thus make the substitution:

[tex]y=\frac{u^{'}}{-u}[/tex]

Turn the crank and get:

[tex]u^{''}-x^2u=0[/tex]

Then solve via power series, then take the derivative, form the quotient, then a plot. Put it all into Mathematica and back-substitute to make sure it's correct, then compare with numerical results. Or just do what you want.

- #6

- 584

- 0

- Last Post

- Replies
- 7

- Views
- 3K

- Last Post

- Replies
- 0

- Views
- 2K

- Last Post

- Replies
- 8

- Views
- 1K

- Replies
- 4

- Views
- 533

- Replies
- 5

- Views
- 1K

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 1K

- Replies
- 4

- Views
- 7K

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 2

- Views
- 6K