Solving the Particle Velocity at Time t=5

AI Thread Summary
The discussion revolves around calculating the velocity of a particle with a mass of 1 kg under a force of F=6(i+t j) N at time t=5 seconds. The acceleration is derived as a = 6i + 6t j, leading to the velocity equation v = (6t)i + (3t^2)j. At t=5, the velocity is determined to be v = 30i + 75j, with a suggestion to also consider its magnitude and direction. Participants note the importance of clearly indicating integration constants and suggest using different letters for clarity. Overall, the solution is confirmed to be correct, with minor recommendations for improvement.
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Homework Statement



At time , t s , a particle with a mass 1 kg moves under the action of force F=6(i+t j) N. If the particles starts to move at time t=0 ,find the velocity of the particle at t=5 .


Homework Equations





The Attempt at a Solution



By F=ma

the acceleration vector , a = 6i+6t j

integrate this gives , v= (6t+c)i+(3t^2+c)j

and when t=0 , v=0

therefore , v=(6t)i+(3t^2)j

and at t=5 s, v=(30)i+(75)j and my next job is to find its magnitude

Is everything all right ?
 
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Yes that looks to be correct, although you can leave your answer in the vectro form v=30i+75j. If you just put the magnitude, you'd need to put the angle as well since velocity is a vector quantity in that it has both magnitude and direction.
 
Just a tiny comment... you write F = ma and then write down a at once. You have used that the mass is equal to 1 here, you might have mentioned that more explicitly, perhaps.

Also the integrations are independent, so the "+ c" that goes with the i-component is not necessarily the same as the "+ c" in the j-component. You would better use different letters for those, for example

v= (6t+c1)i+(3t^2+c2)j
Then from v(t = 0) = 0 (= 0 i + 0 j) it indeed follows that c1 = c2 = 0 (but in general, you can get different constants).

Just some nitpicking from my side though, because you did correctly solve the problem.
 
thank you !
 
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