Solving the Pigeonhole Problem with f(x) for n Elements

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Homework Statement


Let f be a one-to-one function from X = {1,2,...n} onto X. Let f k = f(f(f(...f(x))) be the k-fold composition of f with itself. Show that there are distinct positive integers i and j such that f i (x) = f j (x) for all x in X.


Homework Equations


pigeonhole principle?


The Attempt at a Solution


The section is on counting and the pigeonhole principle. But I'm not sure how to start this one.
 
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Pigeonhole principle, yes. There are only a finite number of possible functions from X->X, yes? There are an infinite number of k's in the set of functions {f^k} for all k. That's a finite number of pigeonholes for an infinite number of k's. Two of the k's must be the same function.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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