Solving the Problem: Work, Power & Friction

AI Thread Summary
To solve the problem, the work done by the force can be calculated using the formula Work = Force * Distance. Given a constant speed of 2.5 m/s over 25 seconds, the distance traveled is 62.5 meters. The power developed can be found using Power = Work / Time. The force of friction can be determined by calculating the net force acting on the object and subtracting it from the applied force. The discussion emphasizes the importance of correctly identifying distance and time in solving work and power problems.
soulja101
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I can't get this question. I've tried everyway i could think but i still can't get it.

A force of 5.0N moves a 6.0kg object along a rough floor at 2.5m/s

11. How much work is done in 25s by the force.
12.what power is being developed.
13. what force of friction is acting on the object(magnitude only).
 
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What have you tried? Pick your best way. Let us see it.
 
I ve tried these formulas force*distance and m*g*h* they still don't work
 
You are on the right track with Force * distance. More details would be nice. What, exactly, did you use for Force and distance? How did you get it?
 
wat i used

i used 5.0N as the force and i got stuck there becuase i couldn't find the distance.
 
Your problem says that the speed is a constant 2.5 m/s. And then it asks how much work is done in 25 s...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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