Solving the Pulley Problem: Find a & T

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Homework Help Overview

The discussion revolves around a pulley problem where participants are tasked with finding the acceleration and tension in a system involving two masses, one of which is hanging. The problem is set in a physics context, specifically focusing on dynamics and forces.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationships between tension and gravitational force, questioning the assumptions about the direction of acceleration and the signs in their equations. Some participants attempt to derive equations based on Newton's second law, while others express confusion about the signs and the physical interpretation of the forces involved.

Discussion Status

The discussion is active, with participants providing insights and clarifications regarding the equations of motion. There is an exchange of ideas about how to properly set up the equations and interpret the results, but no consensus has been reached on the final approach or solution.

Contextual Notes

Participants note the absence of numerical values and the need to express answers in terms of variables such as m, M, g, a, and T. There is also mention of previous experiences with similar problems, indicating a learning process influenced by past mistakes.

blackrose01
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pulley problem :D

Homework Statement


Find the acceleration and tension of the system.
there were no values given so i assumed that our teacher wants the answer in terms of m, M, g, a, T, F.
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Homework Equations


F=ma


The Attempt at a Solution


F=ma
T = F ----> where the F = (mass of hanging block)g
i still don't know about the acceleration though
 
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No, T is not equal to mg.

The mass 'm' has force 'mg' acting downwards, T acting upwards, and it accelerates downwards.

So,
mg - T = ma (net F = ma)

Mass M has just one force, T acting on it.

So,
T = Ma.

You can solve these two equations for T and a in terms of m, M and g.
 


I recently had a question simillar to this on an exam and got it wrong for some reason. I figure the the EQ of motion for the hanging block would be T-mg=-ma, the answer is obviously the one which graphene gave but I don't understand why. The way I visualized this problem was there is tension acting opposite to gravity but my system is accelerating downward so I should, or so I assumed, have a negative acceleration component. Why is this not the case? I see that if I divide my answer through by a negative I get the correct answer, but this is merely an algebraic trick, it doesn't appear to change anything. Thanks in advance.

Joe
 


Agent M27 said:
I recently had a question simillar to this on an exam and got it wrong for some reason. I figure the the EQ of motion for the hanging block would be T-mg=-ma, the answer is obviously the one which graphene gave but I don't understand why. The way I visualized this problem was there is tension acting opposite to gravity but my system is accelerating downward so I should, or so I assumed, have a negative acceleration component. Why is this not the case? I see that if I divide my answer through by a negative I get the correct answer, but this is merely an algebraic trick, it doesn't appear to change anything. Thanks in advance.

Joe

mg-T=ma

this is because the blocks are accelerating and not decelerating.
If you understand this then you can see that acceleration of the block is positive because if is negative. Also mg > T because it is moving downwards.. With knowns your equation would be positive, and just isn't simplified.
 


Do not put any sign on 'a'. Let it just be 'a'. Assume a direction for 'a' and write down Newton's 2nd law. (Net force in the direction of 'a' = ma).
In case you assumed the correct direction for 'a', you'll get a positive answer, else you'll get a negative answer, implying that 'a' points the other way round.
 


Thanks for the explanation. I will remember to leave ma alone until the problem is fully simplified as much as possible. Also as Joshmdmd said since gravity and the direction of motion are in the same direction, it makes sense that it would be mg-T=ma. Take care.

Joe
 

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