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The question is to solve the equation;
2\cot^{2}x + 7cosec x - 13 = 0
for all values of x between 0 and 360. I know I need to use a trig ident, but I've been using several over the course of an hour and I can't seem to get anywhere. Any hints would be helpful
2\cot^{2}x + 7cosec x - 13 = 0
for all values of x between 0 and 360. I know I need to use a trig ident, but I've been using several over the course of an hour and I can't seem to get anywhere. Any hints would be helpful