Solving Two Loop RC Circuit Homework

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Homework Statement



A circuit is constructed with four resistors, one capacitor, one battery and a switch as shown. The values for the resistors are: R1 = R2 = 52 Ω, R3 = 41 Ω and R4 = 129 Ω. The capacitance is C = 62 μF and the battery voltage is V = 24 V.

1) The switch has been open for a long time when at time t = 0, the switch is closed. What is I1(0), the magnitude of the current through the resistor R1 just after the switch is closed?

2) What is I1(∞), the magnitude of the current that flows through the resistor R1 a very long time after the switch has been closed?

3) What is Q(∞), the charge on the capacitor after the switch has been closed for a very long time?

4) Consider the circuit above, with R5 = 119 Ω in series with the capacitor. Once again, the switch has been open for a long time when at time t = 0, the switch is closed. What is I1(0), the magnitude of the current through the resistor R1 just after the switch is closed?

5) Continuing with the new circuit, what is Q(∞), the charge on the capacitor after the switch has been closed for a very long time?

Homework Equations



I=v/r
qmax=C*Vbattery
Q(t)= Qmax(1-e^(-t/T))

The Attempt at a Solution



I have no clue how to do this problem after trying the first few questions. For example I tried the first question and I know after the switch closes, the capacitor acts as a wire, so its just like a circuit with only resistors. I used the equation i=v/r and it didnt work. I tried adding the resistors in different ways but it still didnt work. any help would be awesome. thanks guys!
 

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well resistors in series are added R1 +R2 +R3 etc... i added them all together and then even tried just the inner loop. I know that the current divides at the wire with the resistor. I tried making equations using the loop rule, but there's so many unknowns that I don't think that is the right way to go about this.
 
so the homework program I am using wasnt taking my answer because of the lack of sigfigs. -_-
 
hi fmd826! :smile:

(just got up :zzz:)
fmd826 said:
well resistors in series are added R1 +R2 +R3 etc...

ah, but the right-hand loop aren't in series with the emf …

use the parallel formula to make that loop into one resistor, then put that in series with the emf in the left-hand loop :wink:
 
I am trying to solve part 2 of this question. I know that after a very long time the current decreases, but it is not zero in this case. I used kirchhoffs rules but since Q1, I1, I3 are unknown, I'm clueless on how to find I1 after a very long time..
 
ayajek said:
I am trying to solve part 2 of this question. I know that after a very long time the current decreases, but it is not zero in this case. I used kirchhoffs rules but since Q1, I1, I3 are unknown, I'm clueless on how to find I1 after a very long time..
After a very long time the capacitor will be charged. If the capacitor is fully charged, what do you think the current through the middle branch will be?

Edit:
I just noticed this is a 2 year old thread. You should make a new thread if you have questions.
 
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It's not clear from the problem statement what circuit is associated with parts 1 through 3. The statement mentions four resistors but the only diagram included shows five and appears to be associated with the "new" circuit of parts 4 & 5. Please clarify the circuit configuration for parts 1 through 3.