Solving Variance Problem - Hi All

  • Thread starter Thread starter Asuralm
  • Start date Start date
  • Tags Tags
    Variance
Asuralm
Messages
35
Reaction score
0
Hi all:
If I have a dataset V of the size n*1. Assume that the mean of the dataset is 0 and var(V)=x is its variance. If I want to modify this dataset so that the variance of the new dataset will be var(V_hat)=y. The errors are spreaded average on each element in the dataset. What I did is first calculate the error which need to be speaded on each elements

v_hat - v = delta = sqrt[(y-x)*(n-1) / n] (0)

because

var(V) = x = sum(v^2)/(n-1) (1)
var(V_hat) = y = sum(v_hat^2)/(n-1) (2)

(2)-(1) and rearrange I got the equation (0);

However, this didn't give me the supposed answer. Could anyone point out what's the error in this or if there is any better methods please?
Thanks a lot!
 
Mathematics news on Phys.org
I am not sure what limits you have on the modification. However, you can multiply each element of V by sqrt(y/x) to get what you want.
 
What a nice and easy way. How stupid I am. Thanks a lot!
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top