Solving Vector Equations: Find Value of h

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The discussion focuses on determining the value of h for which the vector b lies in the plane spanned by vectors a_1 and a_2. The approach involves using the augmented matrix formed by these vectors and applying the determinant method to check for coplanarity. It is noted that if the determinant of the matrix is zero, then the vectors are coplanar, allowing for the identification of h. The calculation reveals that h must equal -17 for vector b to be in the plane defined by a_1 and a_2. Thus, the solution confirms that h = -17 is the required value.
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Let a_1 = a column vector with 1, 4, -2; a_2 = a column vector with -2, -3, 7; and b = a column vector with entries 4, 1, h.
(I hope this is an adequate description. I forgot how to write pretty matrices in tex ^_^;)

For what values of h is b in the plane spanned by a_1 and a_2?

I turned this into an augmented matrix but had trouble reducing it to RREF.
 
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I had the best success in vectors when I put everything in terms of dot products and cross products. In this problem, one can take C = a_1 \times a_2 as defining the plane spanned by a_1 and a_2. Then h is in the plane if h \cdot C is zero. That is, if C is perpendicular to h.

Click on this example to be reminded how to format matrices in LaTex with various boundary definitions &c:

\left( \left[ \begin{array}{ccc}<br /> 0 &amp; 1 &amp; 2 \\<br /> 3 &amp; 4 &amp; 5 \end{array} \right| \right)

Carl
 
Put them in a matrix and compute the determinant. If det is 0, then the vector are coplanar and thus, every vector is in the plane span by the other two.

\left| {\begin{array}{*{20}c}<br /> 1 &amp; { - 2} &amp; 4 \\<br /> 4 &amp; { - 3} &amp; 1 \\<br /> { - 2} &amp; 7 &amp; h \\<br /> <br /> \end{array} } \right| = 0 \Leftrightarrow h = - 17
 
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