Solving x Equation: Get Expert Help from Casio

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SUMMARY

The discussion focuses on solving the equation $\frac{2}{3}x - 3 = -x + 2$. The user, Casio, seeks clarification on how to manipulate the equation, specifically how to add x to the left-hand side (LHS). An expert response clarifies that to add x to the LHS, the coefficient must be 1, suggesting $\frac{3x}{3}$ as an appropriate choice. Additionally, it is recommended to multiply each term by three to eliminate the fractions for easier manipulation.

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Casio1
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I have not experienced this one before and would appreciate a little help.

2/3x - 3 = - x + 2
2/3x = - x + 5

Now how do I add x to the LHS, is it;

2/4x or 3/3x or am I completely off the mark?

Kind regards

Casio
 
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Casio said:
I have not experienced this one before and would appreciate a little help.

$\frac{2}{3}x - 3 = -x + 2$
$\frac{2}{3}x = -x + 5$

Now how do I add x to the LHS, is it;

$\frac{2}{4}x$ or $\frac{3}{3}x$ or am I completely off the mark?Kind regards

Casio

If you want to add $x$ to the LHS then the coefficient (number infront of x) must be 1. For fractions this means the top and the bottom must be the same value. $\frac{3x}{3}$ is a good choice in this case.

You may find it easier to multiply each term by three as your first step to clear the fraction altogether.
 

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