The discussion revolves around solving the equation for the variable R, specifically the equation $$\frac{5}{3} = \frac{0.28 + R}{R}$$. Participants express uncertainty about the steps needed to isolate R and address the presence of R in multiple terms.
The conversation includes multiple perspectives on how to approach the problem, with some participants offering different algebraic manipulations. There is no explicit consensus on the best method, but several productive suggestions have been made regarding how to handle the equation.
Some participants note that R appears in multiple places within the equation, which adds to the complexity of the problem. There is also a mention of the original poster's confusion regarding the isolation of R.
Fractions are always a problem. Get rid of them!Jaccobtw said:Homework Statement:: Solve for R. $$\frac{5}{3} = \frac{0.28 + R}{R}$$
Relevant Equations:: Use algebra I guess
The variable is already isolated on one side. I dont' know how to solve for R though. Any help? Thank you.
Ah ok. Multiply both sides by R and then subtract R from both sides. The rest is cakePeroK said:Fractions are always a problem. Get rid of them!
Better yet, multiply both sides of the equation by 3R, and then isolate the terms with R on one side.Jaccobtw said:Ah ok. Multiply both sides by R and then subtract R from both sides. The rest is cake
Although R is only on the right-side, I would not describe that R as "isolated".Jaccobtw said:Homework Statement:: Solve for R. $$\frac{5}{3} = \frac{0.28 + R}{R}$$
Relevant Equations:: Use algebra I guess
The variable is already isolated on one side. I dont' know how to solve for R though. Any help? Thank you.
While true, it may be better to simplify [to reduce the number of R's one sees on]lurflurf said:the difficulty here is R appears twice
we can either merge the R's or eliminate one
to do the later we can...
subtract one from both sides
$$\frac{5}{3} = \frac{0.28 + R}{R}$$
$$\frac{5}{3} -\frac{3}{3}= \frac{0.28 + R}{R}-\frac{R}{R}$$