Some question about number theory

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To prove that if a-c divides ab+cd, then a-c also divides ad+cb, one approach involves manipulating the expressions and applying properties of divisibility. The suggestion to use (a-c)^2(ab+cd) leads to a complex polynomial that may not directly simplify the proof. Instead, exploring the relationship through (a-c)(b-d) could provide a clearer path to the solution. For the second question regarding gcd(a^2+b^2, a+b), it is established that the gcd can only be 1 or 2 when gcd(a,b)=1, based on the properties of coprime integers. These discussions highlight the importance of leveraging divisibility properties and gcd characteristics in number theory.
henry407
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How to prove that if a-c | ab+cd then a-c | ad+cb is correct??
And how to prove the gcd(a^2+b^2, a+b) is 1 or 2. where gcd(a,b)=1.
 
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All I can suggest about the first part is try (a-c)^2(ab+cd)
That can be written as a^3b-2a^2bc-2ac^2d+c^3d+ac(ad+cb)
I'm sure I'm lacking some property that can get from here to the solution. Something like, if x divides y and x divides y+z then x also divides z, or similarly, if x divides y and x divides z, then x divides y+z. Properties like that, but I don't think specifically that one, come into play.
 
Okay forget what I just said. Try (a-c)(b-d)
 
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