Dear colleagues of Physics Forum:(adsbygoogle = window.adsbygoogle || []).push({});

I am trying to estimate the inclination (angle) at which the figure presented with the enclosed photo, composed by two cylinders of different densities (ρ_{1}=2650 kg/m^{3}and ρ_{2}=7000 kg/m^{3}), will topple, when progressively inclined from a horizontal position. Let's assume that both cylinders are glued, that is, they cannot displace between them. Let's also assume that the set will not slide and only "fail" through toppling.

Length of the cylinder 1 is l_{1}=100 mm and length of the cylinder 2 is l_{2}=250 mm. Both pieces have a radius, r = 27 mm. The top one (c2) is displaced r/2 from the centre, in the way shown in the figure below.

Could you help me on calculating the point of toppling (angle)? I tried to estimate it, but I think I should consider momentums in two different axes...and I do not know how to proceed. Also of interest is to calculate the point (location) at which this set will topple around...

[I hope the photo be easy to understand.The set is rotating around the y-axis]

Best regards,

Ignacio

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# I Some questions about toppling of a set of two cylinders

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