- #71
sophiecentaur
Science Advisor
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I think this is a reason for needing to include some damping because the impulse response of your oscillator would extend for all time. If you use a real oscillator (which is the only kind that you can construct in an engineering lab) there is damping and the initial settling time will allow all the natural resonance to dissipate itself. To eliminate it quickly, you need to 'sneak up on it quietly' with your test signal and make sure you don't turn it on at a max or min - or even at a zero, because the time derivative is not continuous.
Your ideal model is implying something that you really can't expect in practice. I have 'squeaked' so many resonant circuits in my time and I have never actually seen this component at ω0 you refer to and the reason is that I have always had damping in there and, with a Q of thousands ( even ) the 'natural' frequency has gone well before you get to measure anything.
Your analysis is quite correct, I think - it just doesn't fit the real world.
Your ideal model is implying something that you really can't expect in practice. I have 'squeaked' so many resonant circuits in my time and I have never actually seen this component at ω0 you refer to and the reason is that I have always had damping in there and, with a Q of thousands ( even ) the 'natural' frequency has gone well before you get to measure anything.
Your analysis is quite correct, I think - it just doesn't fit the real world.