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Sound levels and bernoulli's problems!

  1. Nov 5, 2009 #1

    owl

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    Hi there! Any help would be greatly appreciated. Thanks!

    1. The problem statement, all variables and given/known data

    If a sound level of 0 dB at 1000 Hz corresponds to a maximum gauge pressure (sound amplitude) of 10^-9 atm, what is the maximum gauge pressure in a 50dB sound at the same frequency? (answer: 3x10^-7 atm)

    2. Relevant equations

    L (in dB) = 10 log (I/I0)

    3. The attempt at a solution

    If it is 0 dB that must mean that I0, ie the reference intensity is 10^-9 atm right?

    So ie 0 = 10 log (10^-9/10^-9)
    So to get an answer at 50dB... it would be 50 = 10 log ( ??/10^-9)

    but then I'm getting 50/10 = log ( ??/10^-9)
    10^5 = ?? / 10^-9 (going 10^x both sides to get rid of the log)
    which leaves me with ?? = 10^14 which can't be (and isn't) right...?

    And the other one...

    1. The problem statement, all variables and given/known data

    What is the pressure drop due to the Bernoulli effect as water goes into a 3 cm diameter nozzle from a 9cm diameter fire hose while carrying a flow of 5 x 10^-4 m3s-1? (answer: 247 Pa)

    2. Relevant equations

    So the bernoulli equation is P1 + 1/2 pv12 = P2 + 1/2 pv22
    Leaving out the gravitational parts as horizontal flow is assumed...
    (the little p being density = 1000 kgm^3 for water and the big P being pressure)

    3. The attempt at a solution

    Well rearranging the bernoulli equation to get P2 - P1 I get
    change in P = 1/2 p ( [Q / A1 ]2 - [ Q / A2 ]2 ] ) = 15.44 Pa?

    The answer shows up as 247 Pa which I noticed to be approximately 15.44 squared... but I can't seem to come up with anything other than this!

    Any help would be really appreciated. Thanks!
     
  2. jcsd
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