A certain practical dc voltage source can provide a current of 10.5 A when it is (momentarily) short- circuited, and can provide of 30 W to a 20 Ω load. Find the open-circuit voltage
The Attempt at a Solution
Well I'm pretty sure that the current entering the resistor load would have to be √(3/2), but I'm not sure exactly what to do from there. I don't quite understand what is meant by the 10.5 A when short-circuited statement. Like would that be the current through the source resistance?