Sp3 hybridization azimuthal quantum number

[em3ry]

TL;DR

azimuthal quantum number for sp3 hybridization

The s orbital corresponds to l=0
The p orbital corresponds to l=1

For an electron in an sp3 hybridization orbital what is l?

 

[em3ry]

The answer appears to be 1.5 but I don't know why

 

[em3ry]

n	ℓ	mℓ	ms	mj	j
				mℓ + ms
2	1.5	1.5	+0.5	2	2
2	1.5	0.5	+0.5	1	2
2	1.5	−0.5	+0.5	0	2
2	1.5	-1.5	+0.5	-1	2
2	1.5	-1.5	−0.5	−2	2
2	1.5	-0.5	−0.5	-1	1
2	1.5	0.5	−0.5	0	1
2	1.5	1.5	−0.5	1	1

 

[em3ry]

 

[DrClaude]

n	ℓ	mℓ	ms	mj	j
				mℓ + ms
2	1.5	1.5	+0.5	2	2
2	1.5	0.5	+0.5	1	2
2	1.5	−0.5	+0.5	0	2
2	1.5	-1.5	+0.5	-1	2
2	1.5	-1.5	−0.5	−2	2
2	1.5	-0.5	−0.5	-1	1
2	1.5	0.5	−0.5	0	1
2	1.5	1.5	−0.5	1	1

Where is that from?

sp3 hybrid orbitals are not eigenstates of the orbital angular momentum operator, so it makes no sense to talk about their $l$ value.

 

[em3ry]

I am simply noting that the numbers match the image below it.

And I am no longer sure that it is an image of sp3 hybridization. It might be something else