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Space Station-Artificial Gravity

  1. May 22, 2009 #1
    Determind the minimum diameter of a space station that would simulate an artificial G of 10 m/s^2 at a rotation rate of 1 rpm.



    I was not given an equation, it was one of them 'try to figure it out yourself equations' but I think it is:
    r=9.81g?(pie * rpm/30)^2

    at least that is the equation I got from wiki...




    My attempt at a solution:
    r=9.81(10 m/s^2)/ (pie *1rpm/30)^2
    r =981/.0109
    r =90,000

    then I doubled the ratius to get the diameter:
    d=180,000

    that seems pretty large. i don't know what im doing wrong. if you could help that would be great. thanks.
     
  2. jcsd
  3. May 22, 2009 #2

    Cyosis

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    Where does the 9.81 come from? We are not on earth we're in space there is no gravitational acceleration.

    Instead of finding some formula on wikipedia, are you familiar with the centripetal force?
     
  4. May 22, 2009 #3
    Yes. I am familiar with it.
     
  5. May 22, 2009 #4

    Cyosis

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    Then you can answer this question without having to look up a formula on wiki by using F=ma. Can you see how?
     
  6. May 23, 2009 #5
    Oh okay. Wow, I didn't realize it was that simple. Thanks.
     
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