Spaceship hit the ground with a velocity of 100 m/s

AI Thread Summary
The discussion revolves around understanding the physics of motion, specifically how velocity, acceleration, and force interact in scenarios like a spaceship landing and a ball being thrown upward. It clarifies that negative acceleration indicates a direction (downward due to gravity), which affects how forces are calculated using F=ma. The impact force of the spaceship cannot be determined without knowing its mass, despite its high velocity. When a ball is thrown upward, it decelerates due to gravity until it stops and then accelerates downward, illustrating the relationship between velocity and acceleration. Overall, the conversation emphasizes the importance of direction in physics equations and how momentum plays a role in understanding these concepts.
szekely
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Ok so I'm in 7th grade and I think I'm pretty good in science class. The other day we had some math questions involving some equations. One question was something like a spaceship hit the ground with a velocity of 100 m/s and then it asked like what was its mass. This question also included the gravity of the planet (like 7.8 m/s squared). The next question was what was the force of the impact. The answer was something low because the force of gravity was 7.8. I was wondering how F=ma would work here because the velocity makes it seem like the impact would have much more force than what it was.

Then i started thinking about if you threw a ball straight up. As soon as it left your hand the acceleration would be downward at 9.8 because of gravity. So the acceleration upward is -9.8 even though its still going up. I know that if it hits something while going up its going to have a force so i don't see how F=ma works if acceleration is negative.

Just today i started wondering if this was because of momentum and if you would somehow get p=mv into there.

Thanks for all of the responses. I know this should be extremely easy for you guys.
 
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in these kinds of problems the negative sign is only there to denote direction, with up being the positive direction, and down being the negative(which I am assuming is the convention being used for your class). This applies for forces, momentum, accelerations, velocities, etc.
 


When the ball leaves your hand, a=-9.8m/ss. So it is slowing down. If it hits something on the way up, it will slow down even more quickly, so its deceleration increases to a>-9.8m/ss. This is due to whatever it hit exerting a force on the ball. By Newton's third law, the ball will exert the a force of the same magnitude on whatever it hit. To find out the force, one has to know the change in velocity during the impact, and the duration of the impact.
 


szekely said:
Ok so I'm in 7th grade and I think I'm pretty good in science class. The other day we had some math questions involving some equations. One question was something like a spaceship hit the ground with a velocity of 100 m/s and then it asked like what was its mass.
There must have been more to this question, you do not have enough information to find the mass.
This question also included the gravity of the planet (like 7.8 m/s squared). The next question was what was the force of the impact. The answer was something low because the force of gravity was 7.8. I was wondering how F=ma would work here because the velocity makes it seem like the impact would have much more force than what it was.
If you knew the mass then the force of the impact would indeed be just F = ma with the acceleration being that given.
Then i started thinking about if you threw a ball straight up. As soon as it left your hand the acceleration would be downward at 9.8 because of gravity. So the acceleration upward is -9.8 even though its still going up. I know that if it hits something while going up its going to have a force so i don't see how F=ma works if acceleration is negative.

Just today i started wondering if this was because of momentum and if you would somehow get p=mv into there.

Thanks for all of the responses. I know this should be extremely easy for you guys.

When you throw the ball up it has velocity of +V and acceleration of -g that means (on earth) 9.81 ms-2 down. Since it is accelerating downward its upward velocity is always getting smaller, it is slowing down. When the velocity reaches zero the ball has reached its highest point. It still has a acceleration of -g, so now its velocity begins to increase downward. As it falls in the negative direction (down) its velocity increases due to the acceleration in the negitive direction. When it reaches the point of release its downward speed will equal the speed at which it was released initially. I carefully used the word speed here, since the velocities are not equal, Vup = - Vdown

Does this help?
 
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