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naima
Gold Member
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spacetime states in Rovelli's book "Quantum Gravity"
happy new year everybody,
I am reading "quantum gravity" of Rovelli.
He introduces functions f(x,t) defined on compact of space time that are zero outside.
They correspond to the time and space needed to a measurement.
page 168: they generalize conventional wave packets for which [tex]f(x,t) = f(x) \delta(t) [/tex] which are associated to instantaneous measurements.
There is no equation for them
He constructs the usual wave fonction [tex]\phi(x',t') = \int dx dt w(x',t',x,t) f(x,t)[/tex]
Where w is the propagator. This wave function satisfies the Schrodinger equation.
We lose the information we had with f!
He says f and f' are equivalent iff they give the same [tex]\phi[/tex]
Ok but why have we not to use the information in f?
happy new year everybody,
I am reading "quantum gravity" of Rovelli.
He introduces functions f(x,t) defined on compact of space time that are zero outside.
They correspond to the time and space needed to a measurement.
page 168: they generalize conventional wave packets for which [tex]f(x,t) = f(x) \delta(t) [/tex] which are associated to instantaneous measurements.
There is no equation for them
He constructs the usual wave fonction [tex]\phi(x',t') = \int dx dt w(x',t',x,t) f(x,t)[/tex]
Where w is the propagator. This wave function satisfies the Schrodinger equation.
We lose the information we had with f!
He says f and f' are equivalent iff they give the same [tex]\phi[/tex]
Ok but why have we not to use the information in f?