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The problem is attached.
I don't know why he called all 4 vectors V1, I guess it was a typo.
Anyways, part I) This is not linearly independent as the determinant of the matrix containing those 4 vectors is 0
I am having trouble with part II)
I think I know the answer, but I don't think my explanation is right.
I said you can find a subset of vectors that are linearly independent, BUT not have the same span. The span of the original four vectors is c1v1+c2v2+c3v3+c4v4, where c1,c2,c3, c4 are real #s. The subset is independent, thus, the vectors cannot be written as a linear combination, thus, it doesn't have a span?
I don't know why he called all 4 vectors V1, I guess it was a typo.
Anyways, part I) This is not linearly independent as the determinant of the matrix containing those 4 vectors is 0
I am having trouble with part II)
I think I know the answer, but I don't think my explanation is right.
I said you can find a subset of vectors that are linearly independent, BUT not have the same span. The span of the original four vectors is c1v1+c2v2+c3v3+c4v4, where c1,c2,c3, c4 are real #s. The subset is independent, thus, the vectors cannot be written as a linear combination, thus, it doesn't have a span?
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