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I Special relativity of two clocks

  1. Jun 5, 2016 #1
    Why is it that for two clocks that are synchronised in one frame, S, but not in another, S', is there an offset in the time by a factor of ##\frac{Lv}{c}##, as measured in S'. Where L is the proper length of the body, as measured in S. I'm confused as to why there is not a factor of ##\gamma## here

    Many thanks
     
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  3. Jun 5, 2016 #2

    Orodruin

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    Why do you think there should be a factor ##\gamma##? Have you looked at how the relation is derived?
     
  4. Jun 5, 2016 #3
    I'm pretty sure the offset in time is Lv/c2, not Lv/c (since obviously Lv/c is in units of length).

    Also section 11.3 of this link has a problem that comes up with your Lv/c involving synchronized clocks on a train. It has a nice picture too showing the distance the photon must travel, which gives those two factors.

    http://www.people.fas.harvard.edu/~djmorin/chap11.pdf
     
  5. Jun 6, 2016 #4
    How careless of me- I did mean over ##c^2##. Funnily enough, this was the book that caused my confusion. I don't feel like he explains it very well. However, I have since worked it out- so all it good.

    Thank you for replying though- it's very appreciated :)
     
  6. Jun 7, 2016 #5
    Haha no it definitely could be clearer, but it does have a good picture I think.
     
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