Achmed
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Consider two events that take place at the origin of the frame of an inertial observer O'. At times t_1 ' = 0 and t_2 ' = T. O' moves with a constant speed v w.r.t. another inertial observer O.
1. Use the Lorentz-transformations to show that these events occur at x=vt in the frame of O, at the times t_1 = 0 and t_2 = \gamma T. Show furthermore that the events do not occur at the same place in O, but at x_1=0 and x_2 = \gamma vT.
My attempt below. I am very confused, so I have no idea if what I'm doing is even remotely correct:
Since both events take place at the origin of S', we get that x' = 0. From here it follows using the Lorentz transformation that x=vt.
After this the confusion starts. If we use the Lorentz transformation for time, and we use t'_1 = 0, we actually get t_1 = \dfrac{vx}{c^2}. But this doesn't correspond with what they ask, right? If we do the same for t_2' = T, we get the very same problem. What am I doing incorrectly here?
Using the same tactic above, if I fill in x' = 0 and t_1 = 0 and t_2 = \gamma T, I do get the correct answers for x_1 and x_2! So, that confuses me..
1. Use the Lorentz-transformations to show that these events occur at x=vt in the frame of O, at the times t_1 = 0 and t_2 = \gamma T. Show furthermore that the events do not occur at the same place in O, but at x_1=0 and x_2 = \gamma vT.
My attempt below. I am very confused, so I have no idea if what I'm doing is even remotely correct:
Since both events take place at the origin of S', we get that x' = 0. From here it follows using the Lorentz transformation that x=vt.
After this the confusion starts. If we use the Lorentz transformation for time, and we use t'_1 = 0, we actually get t_1 = \dfrac{vx}{c^2}. But this doesn't correspond with what they ask, right? If we do the same for t_2' = T, we get the very same problem. What am I doing incorrectly here?
Using the same tactic above, if I fill in x' = 0 and t_1 = 0 and t_2 = \gamma T, I do get the correct answers for x_1 and x_2! So, that confuses me..