- #1

emmfranklin

- 7

- 0

## Homework Statement

i getting the wrong the answer

i am

trying to find the specific heat capacity of brass

using copper calorimeter

Data :

mass of brass bob= 32.5gm

mass of calorimeter = 39.7 gm

mass of water + calorimeter = 93.9gm

mass of water = 93.9 - 39.7 = 54.2g

specific heat of water = 4.2 j/gm deg Cel

specific heat of copper = 0.382 j/gm deg cel

Temp of water = 23 deg cel

Temp of brass = 94 deg cel

temp of mixture = 47 deg cel

## Homework Equations

formulas used..

part A

(Mc*cc + Mw*cw)(T1-T2)

(mass of the calorimeter* specific heat of the calorimeter + mass of the water*specific heat of the water)*Fall in the temperature.

Part B

C=H/mΔT

## The Attempt at a Solution

part A being solved

(mass of the calorimeter* specific heat of the calorimeter + mass of the water*specific heat of the water)*Fall in the temperature.

(39.7 * 0.386) + (54.2 * 4.2) * (47-23)

(15.3242 + 227.64) * 24

242.9642 * 24

5831.1408

part b being solved.

C=H/mΔT

= 5831.1408/ 32.5 * 47

= 5831.1408 / 1527.5

= 3.8174407856

specific heat of brass = 3.8174407856 j/gm deg cel

this answer is wrong

the expected answer is 0.3817

where am i going wrong...