Specific Heat (kCal and J) for copper, help please

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SUMMARY

The discussion focuses on calculating the heat required to raise the temperature of a 50-gram cube of copper from 20 degrees Celsius to 45 degrees Celsius using the specific heat values provided. The specific heat of copper is 0.092 kcal/kg·°C and 385 J/kg·°C. The formula used is H = mcΔT, where m is the mass in kilograms, c is the specific heat, and ΔT is the change in temperature. The correct approach involves substituting the known values into the equation to find the heat in both kilocalories and joules.

PREREQUISITES
  • Understanding of specific heat capacity
  • Familiarity with the formula H = mcΔT
  • Ability to convert units between grams and kilograms
  • Knowledge of temperature change calculations
NEXT STEPS
  • Learn how to convert specific heat values between different units (kcal to J)
  • Practice solving heat transfer problems using the formula H = mcΔT
  • Explore the specific heat capacities of other materials for comparative analysis
  • Investigate the implications of specific heat in thermal management applications
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Students studying thermodynamics, physics enthusiasts, and anyone involved in heat transfer calculations will benefit from this discussion.

strayaway
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Homework Statement


How much heat is required to raise the temperature of a 50 gram cube of copper from 20 degrees Celsius to 45 degrees Celsius? (in kcal and J)
Specific Heat(20degrees Celsius) for Copper (kcal/kg x degrees Celsius) is 0.092. and the Specific Heat for Copper (J/kg x degrees Celsius) is 385.


Homework Equations


H = mc (triangle) T


The Attempt at a Solution


so the first thing I did was convert the 50 grams to 0.05 kg, then I set up the equation by putting "H = 0.05kg x 20degrees x 25 degrees. but then that's where i got stuck because I didn't know how to incorporate the specific heat into this.
 
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strayaway said:

Homework Statement


How much heat is required to raise the temperature of a 50 gram cube of copper from 20 degrees Celsius to 45 degrees Celsius? (in kcal and J)
Specific Heat(20degrees Celsius) for Copper (kcal/kg x degrees Celsius) is 0.092. and the Specific Heat for Copper (J/kg x degrees Celsius) is 385.

Homework Equations


H = mc (triangle) T

The Attempt at a Solution


so the first thing I did was convert the 50 grams to 0.05 kg, then I set up the equation by putting "H = 0.05kg x 20degrees x 25 degrees. but then that's where i got stuck because I didn't know how to incorporate the specific heat into this.

I highlighted a couple of items in your post; the thing you wanted to calculate.

You know m - you even converted it to kg; good.
You know C [you were given its value in 2 unit systems, I would be using the SI unit value to find Joules.
You know delta T [20 to 45 equals a change of ...]

Substitute and calculate.
 

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