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Specific heat mixture, final temp, etc.

  • Thread starter 1MileCrash
  • Start date
  • #1
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Homework Statement



The specific heat of lead is 0.03 cal/g*C. 300 grams of lead shot at 100* C is mixed with 100 grams of water at 70* C. What is the final temperature of the mixture if the container is insulated.

Homework Equations





The Attempt at a Solution



Q1 = c1m1(Tf - 100) (lead)
Q2 = c2m2(Tf - 70) (water)

Q1 + Q2 = 0

c1m1(Tf - 100) + c2m2(Tf - 70) = 0
9(Tf - 100) + 100(Tf - 70) = 0
9Tf - 900 + 100Tf - 700 = 0
109Tf = 1600
Tf = 14.7*C = no


EDIT, nevermind... 100 x 70 = 700, you heard it here first!
 
Last edited:

Answers and Replies

  • #2
gneill
Mentor
20,792
2,770
100 x 70 ≠ 700
 
  • #3
1,331
45
100 x 70 ≠ 700
I caught it. :redface:

Works out fine now. Thanks!
 

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