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## Homework Statement

The specific heat of lead is 0.03 cal/g*C. 300 grams of lead shot at 100* C is mixed with 100 grams of water at 70* C. What is the final temperature of the mixture if the container is insulated.

## Homework Equations

## The Attempt at a Solution

Q1 = c1m1(Tf - 100) (lead)

Q2 = c2m2(Tf - 70) (water)

Q1 + Q2 = 0

c1m1(Tf - 100) + c2m2(Tf - 70) = 0

9(Tf - 100) + 100(Tf - 70) = 0

9Tf - 900 + 100Tf - 700 = 0

109Tf = 1600

Tf = 14.7*C = no

EDIT, nevermind... 100 x 70 = 700, you heard it here first!

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