Specific heat mixture, final temp, etc.

[1MileCrash]

Homework Statement

The specific heat of lead is 0.03 cal/g*C. 300 grams of lead shot at 100* C is mixed with 100 grams of water at 70* C. What is the final temperature of the mixture if the container is insulated.

Homework Equations

The Attempt at a Solution

Q1 = c1m1(Tf - 100) (lead)
Q2 = c2m2(Tf - 70) (water)

Q1 + Q2 = 0

c1m1(Tf - 100) + c2m2(Tf - 70) = 0
9(Tf - 100) + 100(Tf - 70) = 0
9Tf - 900 + 100Tf - 700 = 0
109Tf = 1600
Tf = 14.7*C = no


EDIT, nevermind... 100 x 70 = 700, you heard it here first!

 

[gneill]

100 x 70 ≠ 700

 

[1MileCrash]

100 x 70 ≠ 700

I caught it.

Works out fine now. Thanks!