Specifying a hydraulic pump and motor for a class project

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SUMMARY

This discussion focuses on selecting a hydraulic pump and motor for a hydraulic vehicle project, utilizing an existing electric motor rated at 22 kW, 60 Nm, and 3500 rpm. Key calculations indicate that to achieve a hydraulic motor torque of 300 Nm at low speeds (300-500 rpm) and 50 Nm at high speeds (500-1000 rpm), a positive displacement pump with a capacity of 27.3 cc per revolution is required. The discussion emphasizes the importance of considering power efficiency, operating temperature, and pressure limitations (restricted to 2000 psi or 13.8 MPa) to ensure safe and effective operation.

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I am doing a project of hydraulic vehicle. My professor ask our team to install a hydrualic pump and motor in the vehicle. We are considering to purchase a set of hydraulic pump and motor, and we have the following requirements:

  1. We have an existing electric motor of 22kW, 60Nm (continous) and 3500rpm (continous)
  2. For the hydraulic motor, we would like to achieve:
    high torque (300Nm) --> low speed (at least 300-500rpm, can be higher)
    low torque (50Nm) --> high speed (at least 500-1000rpm, can be higher)
    In both cases, the speed (rpm) should be as high as possible.

Does anyone know how to do the calculation? :confused: So that we can select a suitable pump and motor combination for our design. :smile:

I really don't know how to do it, please kindly help me! :cry:

Thank you very much!
 
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You begin by matching the electric power, 22 Kw.

Then survey different hydraulic pump/motor combinations of about rating or less. There are things other than RPM and torque to consider. There is power efficiency, operating temperature, starting torque and more.
 
As an educational project you should not take any risks. For that reason you will restrict pressures to about 2000 psi =13.8 MPa.
From that you can work out the flow rate. Power = flow rate * pressure.
22 kW / 13.8 MPa = 0.0015942 m3/sec =1.5942 litre/sec.

At 3500 RPM you have 3500 / 60 = 58.3 revs per second.
A positive displacement pump capacity will be 1.5942 litre / 58.3 revs = 27.3 cc per rev.
Now you can select a pump based on capacity.

But you must decide how you will control the speed or acceleration of the vehicle. Will you use a variable flow pump and/or bent axis variable speed motors?

Will you run your hydraulic wheel motors in parallel, which has 4 times the flow and equal torque (like a differential), or in series, which will give equal speed ( like four wheel drive) ? Will you switch between various combinations? That will decide the capacity of the motors you use.

Hydraulic transmissions are not used in road motor vehicles because they are inefficient when compared to mechanical gearboxes. Some hydraulic 4WD off-road or earth-moving vehicles may be economic. Assume 60% hydraulic efficiency which means you must dispose of 0.4 * 22kW = 8.8kW. You will need a large oil cooler to keep the fluid temperature down.
 
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