Archived Spectrometer CCD Homework: Calculate Spectral Range for m=4

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The discussion revolves around calculating the spectral range observed by a spectroscopist using a larger CCD plate when changing from order m = 5 to m = 4. The initial parameters include a grating with 600 grooves/mm and a wavelength of 1228 nm. The user attempts to find the angle of diffraction using the equation mλ = d sinθ but struggles with the calculation. It is suggested that the larger CCD may allow for a broader wavelength coverage due to its size. The conversation emphasizes understanding the relationship between the grating, order of diffraction, and the spectral range captured by the CCD.
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Homework Statement


A spectroscopist has a spectrometer equipped with a grating with 600 grooves/mm. This grating puts a 1228 nm wavelength range on a spectroscopic plate (a CCD) in order m = 5. The spectroscopist now changes the spectroscopic plate CCD by one that is larger by a factor of 3. What spectral range will be accepted when the spectroscopist observes the lines in order m = 4 with the new, larger spectroscopic plate?

λ1=1228
d= 1666.67
m1=5
m2=4
λ2=?

Homework Equations



mλ=dsinθ

The Attempt at a Solution



sinθ=[(5)(1228)]/(1666.67)=3.68

However I can't solve for θ, and plug it into another question for m2=4. What step should I do next?

So what exactly does the electroscopic plate do?
 
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woaini said:
wavelength range on a spectroscopic plate (a CCD) in order m = 5. The spectroscopist now changes the spectroscopic plate CCD by one that is larger by a factor of 3.

i think the first set of data gives you an idea of angle at which the experiment is being done - my guess is that angle of diffraction gives you size of CCD detector.
if you use a larger size you may get a larger coverage of wave length /order of diffraction.
 
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