(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A bus goes from the bus stop with the acceleration 0.75 m/s^2. A girl runs after the bus. She has the speed 8.0 m/s, and she was 17.5 m behind the bus as it started.

a) How long time does it take the girl to catch up with the bus?

2. Relevant equations

THe equations for constant acceleration [itex]v=v_0 +at[/itex] and [itex]s=v_0 t + \frac 12 at^2[/itex]

3. The attempt at a solution

I only came as far as to figure out which variables I have for each object:

BUS: [itex]v_0=0 m/s[/itex]since the bus has no speed at the stop, a=0.75m/s^2

GIRL: [itex]v_0=v=8.0 m/s[/itex] Velocity at start is equal to velocity later when the speed is konstant, a=0m/s^2 No acceleration when an object has constant speed. [itex]s_0=-17.5 m[/itex] Starting point 17.5 m behind the bus

However I can't figure out how to use these variables and formulas to get the time it takes her to catch up with the bus....

Please help!

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# Speed and acceleration - running for the bus

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