A uniform electric field has a magnitude of 2.41E+3 N/C. In a vacuum, a proton begins with a speed of 2.27E+4 m/s and moves in the direction of this field. Find the speed of the proton after it has moved a distance of 1.85 mm. alright i looked for some kinematics equations and i used v=d/t. then when i figured out time to be 8.149E-8 i plugged it in to d=1/2(a)(t^2)+(v)(t). i found acceleration to be 2. once i get here im stuck. any help to point me in the right direction would be a great help.