zasvitim said:
It says something strange, which I'm trying to understand. So what will happen according to the second postulate? will there be 2 speeds of reflected photons for each mirror or 1? Will photons somehow split to have speed C for each observer? Does speed of mirror cause any effect on the reflection process and result?
One speed, ##c##. What is misleading you here is that you are making a common sense assumption about how speeds add: if B is moving at speed ##u## relative to A, and C is moving at speed ##v## relative to B, then C's speed relative to A ought to be ##u+v## when C is moving in the same direction as B, ##u-v## when C us moving in the opposite direction.
Here A is the ground, B is the train, C is the flash of light, and this common-sense expectation cannot be reconciled with the second postulate.
However it turns out the common-sense assumption is not right. The correct rule for adding the speeds is not ##u+v##, it is ##(u+v)/(1+uv/c^2)## - this looks a bit simpler if we choose to measure time in seconds and distances in light-seconds so that ##c=1##: we have ##(u+v)/(1+uv)##.
Use this formula and you will find that the flash of light is moving at speed ##c## relative to both the train and the ground.
You may be wondering how it could be that in all the millenia before Einstein discovered relativity no one ever noticed that the common-sense rule was wrong. As an exercise, consider a jet fighter flying at 1000 km/hr firing a 1000 km/hr missile... How fast is the missile going relative to the ground, and how different is that from the 2000 km/hr that the common-sense rule predicts? Do that calculation and you'll see why no one noticed.
(Although around 1850 the physicist Fizeau was working with light passing through moving water and didn't get quite exactly the expected ##u+v## result. At the time this was generally considered to be either a mystery or an experimental error, and it remained that way until it was explained by relativity a half-century later).