Austin0
- 1,160
- 1
kev said:Hi Jake ( and welcome to PF )
I am using coordinate notation such that (x,t) is (distance,time)
Alice's frame (S)
Event A: Alice sends a superluminal signal at (0,0)
Event B: Bob receives the superluminal signal at (10,5)
The signal travels 10 lightseconds in 5 seconds (2c) in Alice's frame.
Bob's frame (S')
Event A' = (0,0)
Event B' = (x',t')
Using the Lorentz transformation
x^{\prime} = \gamma (x - vt)
t^{\prime} = \gamma \left( t - \frac{vx}{c^2} \right)
where \gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}
Assume Bob is moving at 0.8c relative to Alice and units such that c=1.
\gamma = \frac{1}{\sqrt{1 - \frac{0.8^2}{1^2}}} = 1.666
x^{\prime} = 1.666 ( 10 - 0.8*5) = 10
t^{\prime} = 1.666 \left( 5 - \frac{0.8*10}{1^2} \right)= -5
________________________________________________________________________
Hi I apprecciated the clear cut presentation of the maths but couldn't help note a certain paradoxical self negation in your final derivation.
It appears to me that if the signal actually went back in time it couldn't possibly arrive at x=10 and conversely if it did arrive at x=10, it by definition was traveling forward in time no matter what the maths say.
There is the negative time interval: minus 5 seconds.