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## Homework Statement

Using spherical coordinates, find the volume of the solid that lies within the sphere x

^{2}+y

^{2}+z

^{2}=4, above the xy-plane and below the cone z=√(x

^{2}+y

^{2})

## Homework Equations

## The Attempt at a Solution

This is what I have so far,

[tex]v=\int_{0}^{2\pi}\int_{\frac{\pi}{4}}^{\frac{\pi}{2}}\int_{0}^{\frac{2}{cos\phi}}dp d\phi d\theta [/tex]

However, when evaluating this integral you wind up having an infinite discontinuity between the bounds of the 2nd integral, so you can't evaluate it. Am I thinking of the right shape?