Spherical coordinates - phi vs theta

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In spherical coordinates, the angle θ represents the azimuthal angle around the z-axis, while φ represents the polar angle from the z-axis. When θ is held constant, varying the radius r and φ results in a half-plane, as it encompasses all points in that direction. Conversely, when φ is constant, varying θ and r creates a half-cone, as it describes a circular arc extending from the z-axis. The distinction arises from the ranges of these angles, with θ spanning 0 to 2π and φ limited to 0 to π. Understanding this geometric relationship clarifies why one configuration results in a plane and the other in a cone.
Calpalned
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Homework Statement


My textbook states that when ##\theta = c ## where c is the constant angle with respect to the x-axis, the graph is a "half-plane". However, when ##\phi = c ## it is a half-cone. The only difference I see is that ##\phi## is the angle with respect to the z-axis, rather than the x-axis. Why is it that one ends up being a cone and the other a plane?

Homework Equations


n/a

The Attempt at a Solution


That is the only part I don't understand. It is clear how ##\rho = c ## is a sphere, but why are ##\phi## and ##\theta## so different?
 
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Calpalned said:

Homework Statement


My textbook states that when ##\theta = c ## where c is the constant angle with respect to the x-axis, the graph is a "half-plane". However, when ##\phi = c ## it is a half-cone. The only difference I see is that ##\phi## is the angle with respect to the z-axis, rather than the x-axis. Why is it that one ends up being a cone and the other a plane?

Homework Equations


n/a

The Attempt at a Solution


That is the only part I don't understand. It is clear how ##\rho = c ## is a sphere, but why are ##\phi## and ##\theta## so different?

Look at the geometry. If you pick a point where ##\theta = c## and vary ##r>0## and ##\phi## do you see why you get a half plane? Now pick a point where ##\phi = c##. What happens to that point as you vary ##\theta##? When you very ##r##? It might help to be looking at http://en.wikipedia.org/wiki/Spherical_coordinate_system when you answer. Use the second picture there as it has the usual notation used in math.
 
Calpalned said:

Homework Statement


My textbook states that when ##\theta = c ## where c is the constant angle with respect to the x-axis, the graph is a "half-plane". However, when ##\phi = c ## it is a half-cone. The only difference I see is that ##\phi## is the angle with respect to the z-axis, rather than the x-axis.
You are mistaken. For one thing, \theta can range from 0 to 2\pi while \phi only ranges from 0 to \pi. Do you see why that is true?
("Mathematics notation" and "physics notation" reverse \theta and \phi. I am assuming that you are using "mathematics notation".)

Why is it that one ends up being a cone and the other a plane?

Homework Equations


n/a

The Attempt at a Solution


That is the only part I don't understand. It is clear how ##\rho = c ## is a sphere, but why are ##\phi## and ##\theta## so different?
 
How about some physical experience ?

Stand up straight and lift one arm straight up. Let the direction your feet are pointing in represent ##\theta## and the angle your arm makes with the vertical when you lower it represent ##\phi## ("math notation" - I didn't know it existed). Fortunately they have r in common :smile: imagine a very long arm...

Moving your arm up and down (##[0,\pi]##) with feet fixed defines a half plane.
And rotating on your feet (##[0,2\pi]##) with arm angle fixed gives you the cone. (I take it the mistake Ivy refers to is that it's a cone surface, not half a cone).

And now I will revert to "physics notation" in order not to confuse myself :wink: -- after all this is PF and not MF !
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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