Spherical coordinates triple integral

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SUMMARY

The discussion focuses on finding the boundaries for a triple integral using spherical coordinates for the region T defined by 0 ≤ x ≤ 1, 0 ≤ y ≤ √(1 - x²), and √(x² + y²) ≤ z ≤ √(2 - (x² + y²)). The transformation from Cartesian coordinates (x, y, z) to spherical coordinates (r, θ, φ) is essential, utilizing the relations x = r sin(φ) cos(θ), y = r sin(φ) sin(θ), and z = r cos(φ). The Jacobian for this transformation, r² sin(φ), must also be included in the integral setup.

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brad sue
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Hi,

Please can someone help me with this problem:

find the triple integral over T( using spherical coordinate)

T: 0<=x<=1
0<= y<=sqrt(1-x^2)
sqrt(x^2+y^2)<= z <= sqrt(2-(X^2+y^2))


please help me just to find the boundaries of the integrals.
I tried but I did not find the solution of the textbook. ( because I set the wrong triple integral) I also tried to draw a picture but ...nothing


Thank you
 
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Use the relations between Cartesian (x,y,z) and spherical coordinates ([itex]r,\theta,\phi[/tex]) to substitute for x, y and z:<br /> <br /> [tex]x=rsin(\phi)cos(\theta)[/tex]<br /> [tex]y=rsin(\phi)sin(\theta)[/tex]<br /> [tex]z=rcos(\phi)[/tex]<br /> <br /> where phi is the angle between a vector and the z-axis. theta is the angle between the projection on the x,y plane ad the x-axis.[/itex]
 
Also don't forget your Jacobian, in this case being r²sin(phi).
 

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