Splitting an integral with an absolute value

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Homework Help Overview

The problem involves evaluating an integral with an absolute value in the context of calculus, specifically focusing on the expression \(\int_{-\infty}^{\infty}(x/x_0)e^{-2|x|/x_0} dx\), where \(x_0\) is a constant. The original poster is seeking assistance in properly splitting the integral for integration.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to split the integral into two parts, questioning whether to maintain the negative sign in the lower integral. Some participants suggest comparing the integrand \(f(x)\) with \(f(-x)\) to explore simplifications.

Discussion Status

Participants are engaged in exploring different approaches to the integral, with some guidance provided regarding the relationship between the two parts of the integral. There is an acknowledgment of the complexity introduced by the term \(x/x_0\) and the need for careful consideration in the integration process.

Contextual Notes

There is a mention of the original poster's struggle with LaTeX formatting, which may indicate a focus on clarity in mathematical expression. The discussion also reflects on the implications of integrating by parts and the relationship between the integrals over different intervals.

Koshi
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This is a physics problem, but I only need help with the calculus portion of it. I was having trouble figuring out how to split the integral to properly integrate.


Homework Statement




Homework Equations



\int\stackrel{\infty}{-\infty}(x/x_0)e-2|x|/x_0dx

where x_o is a constant

The Attempt at a Solution



I was wondering how to write the lower part of the integral. What I have is

\int\stackrel{0}{-\infty}(x/x_0)e2x/x_0dx+\int\stackrel{\infty}{0}(x/x_0)e-2x/x_0dx

Is that right or should I keep the negative in front of the 2 in the lower integral?
 
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You've got it right. But there is an easy way to do your integral. If f(x) is the integrand, how does f(x) compare with f(-x)?
 
Fixed the LaTeX in your first integral. Double-click it to see what I did.
Here are some tips:
Use only a single pair of [ tex] and [ /tex] tags (without the leading spaces that I show) for a given expression. You had tex tags around almost every item.
Don't mix [ sup] and [ sub] tags inside [ tex] tags. They don't work. Instead use ^{} for superscripts and _{} for subscripts.
Koshi said:
This is a physics problem, but I only need help with the calculus portion of it. I was having trouble figuring out how to split the integral to properly integrate.


Homework Statement




Homework Equations



\int_{-\infty}^{\infty}(x/x_0)e^{-2|x|/x_0} dx

where x_o is a constant

The Attempt at a Solution



I was wondering how to write the lower part of the integral. What I have is

\int\stackrel{0}{-\infty}(x/x_0)e2x/x_0dx+\int\stackrel{\infty}{0}(x/x_0)e-2x/x_0dx

Is that right or should I keep the negative in front of the 2 in the lower integral?
 
Mark44 said:
Fixed the LaTeX in your first integral. Double-click it to see what I did.

Thanks for the fix. I was struggling with it :P
 
Dick said:
You've got it right. But there is an easy way to do your integral. If f(x) is the integrand, how does f(x) compare with f(-x)?

I was thinking I could just double the integral from 0 to \infty but because there was an x/x_0 in front and I would have to integrate by parts, I reasoned against it.

I wouldn't know how else to simplify it.
 
Koshi said:
I was thinking I could just double the integral from 0 to \infty but because there was an x/x_0 in front and I would have to integrate by parts, I reasoned against it.

I wouldn't know how else to simplify it.

Yes, if you want to do the integral from 0 to infinity you should integrate by parts. But you can't double it to get the whole integral because the integral from -infinity to 0 isn't the same. How are the two integrals related? You could, of course, just do the integration and find out... But you would be going to a lot of extra work.
 

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